PHP MySQL一次插入/更新多行 - PHP MySQL insert/update multiple rows at once

我读过这个问题：https://stackoverflow.com/questions/20255690/php-insert-a-variable-number-of-records-to-mysql-from-a-html-form#=

但我不知道如何将其应用于具有多个输入的表单。我希望这些输入进入同一行（每个数组id）。

我的PHP呈现以下HTML:

<div class="panel-body">
    <div class="row">
        <div class="col-xs-12 col-sm-6 col-md-4 col-lg-3 employee-container">
            <label for="visible-107">
                <img title="Jane Doe" src="/images/prof-pics/default.jpg" class="img-responsive img-circle" alt="Jane Doe">
            </label>
            <h4><input type="checkbox" name="visible[0]" id="visible-107"> <label for="visible-107">Jane Doe</label></h4>
            <div class="input-group">
                <span class="input-group-addon">Function</span>
                <input type="text" class="form-control" name="function[0]" id="function-107">
            </div>
            <div class="input-group">
                <span class="input-group-addon">Order</span>
                <select class="form-control" name="order[0]" id="order-107">
                    <option value="">-- select one --</option>
                    <option value="1">1</option>
                    <option value="2">2</option>
                    <option value="3">3</option>
                    <option value="4">4</option>
                </select>
            </div>
            Description<br>
            <textarea class="form-control" name="description[0]" id="description-107"></textarea>
        </div>
        <div class="col-xs-12 col-sm-6 col-md-4 col-lg-3 employee-container">
            <label for="visible-2"><img title="John Doe" src="/images/prof-pics/default.jpg" class="img-responsive img-circle" alt="John Doe"></label>
            <h4><input type="checkbox" name="visible[1]" id="visible-2"> <label for="visible-2">John Doe</label></h4>
            <div class="input-group">
                <span class="input-group-addon">Function</span>
                <input type="text" class="form-control" name="function[1]" id="function-2">
            </div>
            <div class="input-group">
                <span class="input-group-addon">Order</span>
                <select class="form-control" name="order[1]" id="order-2">
                    <option value="">-- select one --</option>
                    <option value="1">1</option>
                    <option value="2">2</option>
                    <option value="3">3</option>
                    <option value="4">4</option>
                </select>
            </div>
            Description<br>
            <textarea class="form-control" name="description[1]" id="description-2"></textarea>
        </div>
    </div>
</div>

我该如何迭代这些数组，以便将它们作为每个数组ID的一行插入/更新？

在实现Nana Partykar的答案之后

function set_team($web_mysqli, $mysqli, $uid, $visible, $function, $order, $description, $action, $update_id = null ) {
    $number_empl = sizeof($function);
    for($i=0; $i<$number_empl; $i++) {
        $uid = $uid[$i];
        $visible = $visible[$i];
        $function = $function[$i];
        $order = $order[$i];
        $description = $description[$i];
        $name = get_full_name($mysqli, $uid, false);
        $sql = "INSERT INTO team (name, function, description, displayorder, visible) VALUES ('$name', '$function', '$description', '$order', '$visible')";
        $web_mysqli->query($sql) or die(mysqli_error($web_mysqli));
    }
    $_SESSION['success'] = "Employee list website updated";
    header("Location: ".BASE_PATH."/includes/views/list-employees.php");
    exit();
if(isset($_POST['submit-btn'])) {
    set_team($web_mysqli, $mysqli, $_POST['uid'], $_POST['visible'], $_POST['function'], $_POST['order'], $_POST['description'], 'insert');
}

当我保存时，表中只插入第一个名字，后面跟着3行空白。

无需name[0]、

<input type="checkbox" name="visible[0]" id="visible-107">
<input type="text" class="form-control" name="function[0]" id="function-107">
<select class="form-control" name="order[0]" id="order-107">
<textarea class="form-control" name="description[0]" id="description-107"></textarea>

制作

<input type="checkbox" name="visible[]" id="visible-107">
<input type="text" class="form-control" name="function[]" id="function-107">
<select class="form-control" name="order[]" id="order-107">
<textarea class="form-control" name="description[]" id="description-107"></textarea>

SomePage.php（提交页面）

<?
extract($_POST);
$sizeOfFunc=sizeof($function);
for($i=0;$i<$sizeOfFunc;$i++)
{
    $Visible=$visible[$i];
    $Function=$function[$i];
    $Order=$order[$i];
    $Description=$description[$i];
    echo $Visible." ".$Function." ".$Order." ".$Description;
    //Use $Visible, $Function, $Order, $Description in your query
}
?>

更新的代码

不要使用相同的变量名。至少更改变量名称。

这是错误的。

$uid = $uid[$i];
$visible = $visible[$i];
$function = $function[$i];
$order = $order[$i];
$description = $description[$i];

这是正确的

$Uid = $uid[$i];
$Visible = $visible[$i];
$Function = $function[$i];
$Order = $order[$i];
$Description = $description[$i];

我更改了你的密码。使用以下代码。它会起作用的。

<?
function set_team($web_mysqli, $mysqli, $uid, $visible, $function, $order, $description, $action, $update_id = null ) {
    $number_empl = sizeof($function);
    for($i=0; $i<$number_empl; $i++) {
        $Uid = $uid[$i];
        $Visible = $visible[$i];
        $Function = $function[$i];
        $Order = $order[$i];
        $Description = $description[$i];
        $name = get_full_name($mysqli, $Uid, false);
        $sql = "INSERT INTO team (name, function, description, displayorder, visible) VALUES ('$name', '$Function', '$Description', '$Order', '$Visible')";
        $web_mysqli->query($sql) or die(mysqli_error($web_mysqli));
    }
    $_SESSION['success'] = "Employee list website updated";
    header("Location: ".BASE_PATH."/includes/views/list-employees.php");
    exit();
if(isset($_POST['submit-btn'])) {
    set_team($web_mysqli, $mysqli, $_POST['uid'], $_POST['visible'], $_POST['function'], $_POST['order'], $_POST['description'], 'insert');
}
?>

编辑后，我在系统中检查了您的代码。它运行良好。

<?
error_reporting(0);
extract($_POST);
echo $number_empl = sizeof($function);
for($i=0; $i<$number_empl; $i++) 
{
    $Visible = $visible[$i];
    $Function = $function[$i];
    $Order = $order[$i];
    $Description = $description[$i];
    $name="Just";
    echo $sql = "INSERT INTO team (name, function, description, displayorder, visible) VALUES ('$name', '$Function', '$Description', '$Order', '$Visible')"."<br>";
}
?>