我正在尝试解析twitter用户统计数据（使用php）——我对解析json非常不熟悉，所以这让我有点头疼（我知道这里遗漏了一些愚蠢的东西）。我看了很多其他人的回答/帖子，但都记不清了。任何帮助都很感激。
本质上，我想要得到的是[url]和[text]，但我在php中不断出现错误。
[0] => stdClass Object
(
[in_reply_to_user_id] =>
[in_reply_to_status_id_str] =>
[retweet_count] => 0
[id_str] => 180735710897250304
[in_reply_to_user_id_str] =>
[geo] =>
[favorited] =>
[user] => stdClass Object
(
[id_str] => 46023
[id] => 460
)
[in_reply_to_status_id] =>
[in_reply_to_screen_name] =>
[truncated] =>
[contributors] =>
[source] => Facebook
[entities] => stdClass Object
(
[hashtags] => Array
(
)
[urls] => Array
(
[0] => stdClass Object
(
[expanded_url] => http://www.buzzfeed.co
[url] => http://t.c
[indices] => Array
(
[0] => 0
[1] => 20
)
[display_url] => buzzfeed.com/c
)
[1] => stdClass Object
(
[expanded_url] => http://fb
[url] => http://t.
[indices] => Array
(
[0] => 21
[1] => 41
)
[display_url] => fb.m
)
)
[user_mentions] => Array
(
)
)
[coordinates] =>
[retweeted] =>
[id] => 180735
[created_at] => Fri Mar 16 19:22:06 +0000 2012
[possibly_sensitive] =>
[place] =>
[text] => http://t.co
json_decode函数采用可选的第二个参数来返回关联数组，而不是对象。
尝试：json_decode($your_json_var, false)
然后，您可以像使用任何数组一样正常地检索值。
您还可以获得以下值，例如：
echo $tweets[0]->id_str;
这将显示json数据中的id_str值。