我需要根据用户的状态显示不同的措辞。我意识到while()变量超出了Online_status()的范围,但我不知道如何共享变量,甚至不知道如何在与while(。我已经尝试将Online_Status()放在while()中、while周围()、while之外()和其他配置中好几个小时了。没有发生。如果有任何帮助,我将不胜感激!
<?php
require_once('connect.php');
$con = mysqli_connect(DBHOST, DBUSER, DBPASS, DBNAME) or die('Connection failed: ' . mysqli_connect_error());
$sql = mysqli_query($con, "SELECT UserType, Online, InChat FROM membership WHERE UserType = 2 ORDER BY Online DESC");
while($row = mysqli_fetch_array($sql)){
$UserType = $row['UserType'];
$Online = $row['Online'];
$InChat = $row['InChat'];
echo Online_Status();
}
function Online_Status(){
if ($Online == 0) {
echo "I am not online. Please come back later";
}
else if($Online == 1 && $InChat == 0){
echo "I am Online and I will be in my chatroom shortly.";
}
else if($Online == 1 && $InChat == 1){
echo "I am Online chat with me now!";
}
}
mysqli_close($con);
?>
使用global
关键字:
function Online_Status(){
global $Online;
if ($Online == 0) {
echo "I am not online. Please come back later";
}
}
最好通过函数参数传递变量:
function Online_Status($Online){
if ($Online == 0) {
echo "I am not online. Please come back later";
}
}
并称之为:
Online_Status($Online);
此外,还可以看看PHP
的变量作用域。