如何在 php 中添加另一个其他函数


How to add another else function in php

你好,我需要一些关于php的帮助。我正在尝试在 html 中创建一个表单并使用 php 来验证密码输入是否像密码 2 和电子邮件一样无效......

我已经构建了它,但我现在正在尝试在输入验证器的末尾放置一个(else)。

我总是收到错误:解析错误:语法错误,C:''xampp''htdocs''main''register.php 第 82 行中意外的"else"(T_ELSE

<?PHP
session_start();
$something=$_POST["something"];
$something=$_POST["something"];
$something=$_POST["something"];
$something=$_POST["something"];
$something=$_POST["something"];
$something=$_POST["something"];
if($serverSettings['register_on'] && (!isset($_SESSION['something']) && !checkInt($_SESSION['something']) && !$_SESSION['something']>=0)) {
if(isset($_POST['submit']) && $_POST['submit'] == 'Registar') {
    if((checkAnum($_POST['something']) && strlen($_POST['something'])>=4 && strlen($_POST['something'])<=16) && 
    checkAnum($_POST['password'])  && strlen($_POST['password'])>=8 && strlen($_POST['password2'])<=16 && !empty($_POST['password2']) && 
    (checkName($_POST['something']) && strlen($_POST['something'])>=3 && strlen($_POST['something'])<=20) && $_POST['password']==$_POST['password2'] && 
    checkMail($_POST['email']) && strlen($_POST['email'])<=40 && $_POST['email']==$_POST['email2'] && 
    (checkAnum($_POST['something']) && strlen($_POST['something'])>=3 && strlen($_POST['something'])<=16) && 
    (checkAnum($_POST['something']) && strlen($_POST['something'])==7)) {
        require_once("***/configfilee.php");
        mysql_select_db("ahsdsdbdi2");
        $exec="select * from account where login='$something'";
        $result=mysql_query($exec);
        $rs=mysql_fetch_object($result);
        if($rs){
            echo "<center><b><font color='#ff0000'>Registo falhou:</font> This account already exists.</b></center>";
        }
        else {
          $exec="insert into account (something,something,something,something,something,something)  values('$something',something('$something'),'$something','$something','$something','$something')";
          mysql_query("set names big5 ");
          mysql_query("set CHARACTER big5 ");
          mysql_query($exec);
            echo "<center>
            <h1><u>Registration completed successfully.</u></h1><br />";exit;
        }
    }`enter code here`
    HERE IS MY PROBLEM-> else {
      echo "<p>Something is wrong!</p>";
    }
}
?>

如果您在查看代码时遇到问题,这里有一个显示它的链接:https://dl.dropboxusercontent.com/u/104961902/code.txt

你的第一个if语句没有关闭

我认为您在文件的最后缺少一个}

更改此设置:

    echo "<p>Something is wrong!</p>";
    }
}
?>

对此(以及最后的额外}

            echo "<p>Something is wrong!</p>";
        }
    }
}

?>

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