cakePHP 从自定义数组构建一个选择框


cakePHP build a select box from custom array

所以我们有各种各样的搜索页面,每个页面都有不同的搜索条件,所以我决定编写一个组件,它将从控制器获取传递给它的参数,收集必要的数据并返回一个数组,然后我可以将其设置为在我的视图文件中使用,以填充下拉框以过滤条件。

我已经设法将所有内容都写到我必须使用 cakePHP 助手来构建动态选择框的地方。我确信我做错了什么,如果有更简单的方法可以做到这一点并且仍然保持一定的动态性,请在可能的情况下提供帮助:

// COMPONENT METHOD:
 public function filterQueries($parameters) {
    // Get defaults from the user:
    $criteria = $parameters["custom"];
    $defaults = $parameters["defaults"];
    // Validate the defaults the user may want and assign them to the return array:
    if($defaults != "false") {
        foreach($defaults as $key => $value) {
            if(array_key_exists($value, $this->defaults)) {
                $this->returnArray["defaults"][$value] = $this->defaults[$value];
            }
        }
    }
    // Get all data for the custom requested form fields:
    if($criteria != false) {
        foreach($criteria as $model => $arguments) {
            $fields = $arguments["fields"];
            $conditions = $arguments["conditions"];
            $recursive = $arguments["recursive"];
            if(!in_array($model,$this->uses)) {
                $useModel = ClassRegistry::init($model);
            } else {
                $useModel = $this->$$model;
            }
            $array = $useModel->find("all",array("conditions" => $conditions, "fields" => $fields, "recursive" => $recursive));
            $this->returnArray["custom"][$model] = $array;
        }
    }
    return $this->returnArray;
}

上面的函数将获得一个分解自定义搜索或默认值的数组(上面未包含,但它都可以正常工作,它完全按照我的预期返回数组。

 // The code within my action to get the content from above:
// Load the Filters component to search data:
        $search = $this->Components->load("Filter");
        // Tell search what you want:
        $searchBoxes = array(
            "defaults" => array("statuses", "survey_type"),
            "custom" => array(
              "User" => array(
                  "fields" => array("User.id","User.first_name", "User.last_name"),
                  "conditions" => array("User.user_group_id" => "4f847c63-1840-446e-88be-3e4d29566cf0"),
                  "recursive" => -1
              )  
            )
        );
       $filterResults = $search->filterQueries($searchBoxes);
       $this->set("filters",$filterResults);

所以现在我在我的视图文件中得到了这个多关联数组(一切仍然很好),但我现在想根据上面创建的数组构建一个用户下拉列表的示例,但结果与我预期的完全不同:

echo $this->Form->input('user_id',
                        array(
                            "type" => "select",
                            "options" => $filters["custom"]["User"]
                        )
                     );

HTML 输出已损坏,并按如下所示显示:

<option value="last_name">Doe</option>
<option value="first_name">Jihn</option>
<optgroup label="User"> </optgroup>
<optgroup label="1"> </optgroup>
<option value="last_name">Marilyn</option>
<option value="first_name">Monroe</option>

我承认我没有很多蛋糕经验,但不明白如何获得结果:

 <option value='USERID'>NAME</option> // Yes I know the names and surnames must be concatinated still

任何关于如何做到这一点的建议帮助或指导,并以正确的方式做,将不胜感激:)

VARDUMP on $filters['custom']['users']

  array
   0 => 
     array
       'User' => 
         array
            'id' => string '4f84840e-cda8-4704-8fdf-210729566cf0' (length=36)
            'first_name' => string 'Name' (length=4)
            'last_name' => string 'Surname' (length=11)
    1 => 
      array
        'User' => 
          array
            'id' => string '4f8488cb-53e0-4f72-af73-3de229566cf0' (length=36)
            'first_name' => string 'Name' (length=6)
            'last_name' => string 'Surname' (length=6)

您可以通过执行以下操作来增强输出:

1)为了组合表的两个字段,可以在模型中使用"virtualfields",如下所示: 例如,如果您有用户模型,则可以定义如下:

 public $virtualFields = array(
  'full_name' => 'CONCAT(first_name, " ",last_name)'
 );

因此,现在,每当调用用户模型的find方法时,都会获得"full_name"字段。

2)要从表中获取选择框的数据,可以使用find('list')方法。例如,对于用户模型,如果您需要表的id,full_name (last and first name combined using the virtual fields),可以按如下方式完成:

$this->User->find('list',array('fields'=>array('id','full_name'),'conditions'=>$conditions))

我希望这有帮助..

好吧,

我想您实际上要做的是使用格式化选项创建另一个数组。

foreach ($filters["custom"]["User"] as $arr)
{
    $options[$arr['id']] = $arr['first_name'] . ' ' . $arr['last_name'];
}

然后

echo $this->Form->select('user_id', $options);

我认为你需要这样的东西:

$result = Set::combine($filters["custom"]["User"], 
                       '{n}.User.id', // this is the value of select box
                         array(
                               '{0} {1}', 
                               '{n}.User.first_name', 
                               '{n}.User.last_name'
                              ) // this is the text of select box
                      );
pr($result);

$this->form->input('inputname', array

('label' => false, 'options' => array('Select optionstype','a','b'), 'class'=>array('form-a', 'b'), 'id' => 'bacid', 'style' => 'width:280px;','value'=>$abc['model']['array_attribute']));

在 cakePHP 3 上,我还不能使用"virtualFields",但我可以使用如下方式:

//In PostsController
$users = $this->Posts->Users->find('list', 
['keyField'   => 'id', 
 'valueField' => 'full_name', //Don't forget to call concatened field here
 'conditions' => $conditions, 
 'order'      => $orderBy 
]);
//here the magic happens
$concat = $users->func()->concat(
['Users.first_name' => 'identifier', 
 ' ', 
 'Users.last_name' => 'identifier'
]);
//selecting fields
$users->select(['id', 'full_name' => $concat]);
//sending to view
$this->set('users', $users->toArray());

我希望这对 CakePHP 3 开发人员有所帮助