PDO“关于重复键更新”准备的声明


PDO "ON DUPLICATE KEY UPDATE" prepared statement

我第一次尝试基于此线程进行预准备语句。到目前为止,我收到错误消息SQLSTATE[HY000]: General error: 1 near "ON": syntax error 下面是查询后跟try块:

$query = "INSERT INTO results2015_2016 ('id','ata','atc','atcommon','atn','ats','atsog','hta','htc','htcommon','htn','hts','htsog','bs','bsc','canationalbroadcasts','gcl','gcl1','gs','r1','usnationalbroadcasts')
          VALUES (':id',':ata',':atc',':atcommon',':atn',':ats',':atsog',':hta',':htc',':htcommon',':htn',':hts',':htsog',':bs',':bsc',':canationalbroadcasts',':gcl',':gcl1',':gs',':r1',':usNationalBroadcasts')
          ON DUPLICATE KEY UPDATE id= ':id2'";
try {   
    $db = new PDO('db info');  
    $db->setAttribute(PDO::ATTR_ERRMODE,PDO::ERRMODE_EXCEPTION);  
    $stmt = $db->prepare($query);
    $stmt->bindParam(':ata', $ata, PDO::PARAM_STR);
    $stmt->bindParam(':atc' , $atc , PDO::PARAM_STR);
    $stmt->bindParam(':atcommon', $atCommon , PDO::PARAM_STR);
    $stmt->bindParam(':atn', $atn , PDO::PARAM_STR);
    $stmt->bindParam(':ats', $ats , PDO::PARAM_INT);
    $stmt->bindParam(':atsog', $atsog , PDO::PARAM_INT);
    $stmt->bindParam(':hta', $hta , PDO::PARAM_STR);
    $stmt->bindParam(':htc', $htc , PDO::PARAM_STR);
    $stmt->bindParam(':htcommon', $htCommon , PDO::PARAM_STR);
    $stmt->bindParam(':htn', $htn , PDO::PARAM_STR);
    $stmt->bindParam(':hts', $hts , PDO::PARAM_INT);
    $stmt->bindParam(':htsog', $htsog , PDO::PARAM_INT);
    $stmt->bindParam(':bs', $bs , PDO::PARAM_STR);
    $stmt->bindParam(':bsc', $bsc , PDO::PARAM_STR);
    $stmt->bindParam(':canationalbroadcasts', $caNationalBroadcasts , PDO::PARAM_STR);
    $stmt->bindParam(':gcl', $glc , PDO::PARAM_BOOL);
    $stmt->bindParam(':gcl1', $glc1 , PDO::PARAM_BOOL);
    $stmt->bindParam(':gs', $gs , PDO::PARAM_INT);      
    $stmt->bindParam(':r1', $r1 , PDO::PARAM_BOOL);
    $stmt->bindParam(':usnationalbroadcasts', $usNationalBroadcasts , PDO::PARAM_STR);
    $stmt->bindParam(':id', $idGame , PDO::PARAM_INT);
    $stmt->bindParam(':id2', $idGame , PDO::PARAM_INT);
    $stmt->execute();
} catch (Exception $e) {  
        echo $e->getMessage();
        exit;
    }   

似乎找不到太多关于此错误消息以及它与我的情况有什么关系的信息。此代码在循环解析 jsonp 中...如果需要,我可以发布整个代码。

使用预准备语句时,不需要将参数括在任何类型的引号中。这将由引擎本身处理:

$query = "INSERT INTO x(a,b,c,d) VALUES(:a, :b, :c, :d)";

正如@HJPotter92所指出的 - sql 中的占位符不应被引用,还应该注意字段名称应该用反引号而不是单引号括起来(或者如果名称不被视为保留并且不包含空格等,则什么都没有(

$query = "insert into results2015_2016 (
              `id`,`ata`,`atc`,`atcommon`,`atn`,`ats`,`atsog`,`hta`,
              `htc`,`htcommon`,`htn`,`hts`,`htsog`,`bs`,`bsc`,`canationalbroadcasts`,`gcl`,`gcl1`,
              `gs`,`r1`,`usnationalbroadcasts`
          ) values (
             :id,:ata,:atc,:atcommon,:atn,:ats,:atsog,:hta,:htc,:htcommon,:htn,:hts,
             :htsog,:bs,:bsc,:canationalbroadcasts,:gcl,:gcl1,:gs,:r1,:usnationalbroadcasts
          ) on duplicate key update id=:id2";