如何计算 PHP 中的日期戳的持续时间？ 我在日期之间使用的日期格式是"Y-m-d H：i：s"，
我的工作代码只能计算时间段之间的持续时间，而不考虑日期。
下面是我的代码：
$assigned_time = "2012-05-21 22:02:00";
$completed_time= "2012-05-22 05:02:00";
function hmsDiff ($assigned_time, $completed_time) {
$assigned_seconds = hmsToSeconds($assigned_time);
$completed_seconds = hmsToSeconds($completed_time);
$remaining_seconds = $assigned_seconds - $completed_seconds;
return secondsToHMS($remaining_seconds);
}
function hmsToSeconds ($hms) {
$total_seconds = 0;
list($hours, $minutes, $seconds) = explode(":", $hms);
$total_seconds += $hours * 60 * 60;
$total_seconds += $minutes * 60;
$total_seconds += $seconds;
return $total_seconds;
}
function secondsToHMS ($seconds) {
$minutes = (int)($seconds / 60);
$seconds = $seconds % 60;
$hours = (int)($minutes / 60);
$minutes = $minutes % 60;
return sprintf("%02d", abs($hours)) . ":" .
sprintf("%02d", abs($minutes)) . ":" .
sprintf("%02d", abs($seconds));
}
DateTime 有一个返回 Interval 对象的"diff"方法。间隔对象有一个方法"格式"，允许您自定义输出。
#!/usr/bin/env php
<?php
$assigned_time = "2012-05-21 22:02:00";
$completed_time= "2012-05-22 05:02:00";
$d1 = new DateTime($assigned_time);
$d2 = new DateTime($completed_time);
$interval = $d2->diff($d1);
echo $interval->format('%d days, %H hours, %I minutes, %S seconds');
注意：如果您不使用 5.3.0+，这里有一个很好的答案：https://stackoverflow.com/a/676828/128346。
不完全知道你想要什么，像这样的事情呢：
// prevents php error
date_default_timezone_set ( 'US/Eastern' );
// convert to time in seconds
$assigned_seconds = strtotime ( $assigned_time );
$completed_seconds = strtotime ( $completed_time );
$duration = $completed_seconds - $assigned_seconds;
// j gives days
$time = date ( 'j g:i:s', $duration );