我在使用 PHP 从 XML 文件中删除记录时遇到问题。
我不断收到以下错误：
致命错误：无法在第 19 行的/Applications/XAMPP/xamppfiles/htdocs/catalog/deleteaction.php 中使用 DOMElement 类型的对象作为数组
这是代码：
.XML
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="catalogue_overview.xsl"?>
<catalogue>
<record>
<catId>001</catId>
<title>Fungus</title>
<location>GP</location>
<photographer>jrm</photographer>
<equipment>Canon EOS 40D</equipment>
<caption>Small fungus</caption>
<notes>This is a very rare species of fungus</notes>
<date>10/8/2012</date>
<imageUrl>images/IMG_1684.jpg</imageUrl>
</record>
</catalogue>
.PHP目录删除.php
!doctype html>
<html>
<head>
<meta charset="UTF-8">
<title>Photo Catalogue - Delete Entry</title>
<link rel="stylesheet" type="text/css" href="css/style.css"/>
</head>
<body>
<h1>Delete Entry From Catalogue</h1>
<p>DDDDDDD</p>
<?
echo "<form action='deleteaction.php' method='post'>'n";
$doc = new DOMDocument();
$doc->load('catalogue.xml');
$catdelete = $doc->getElementsByTagName("record");
foreach($catdelete as $record) {
$catIds = $record->getElementsByTagName( "catId" );
$catId = $catIds->item(0)->nodeValue;
$titles = $record->getElementsByTagName( "title" );
$title = $titles->item(0)->nodeValue;
$locations = $record->getElementsByTagName( "location" );
$location = $locations->item(0)->nodeValue;
$photographers = $record->getElementsByTagName( "photographer" );
$photographer = $photographers->item(0)->nodeValue;
$equip = $record->getElementsByTagName( "equipment" );
$equipment = $equip->item(0)->nodeValue;
$captions = $record->getElementsByTagName( "caption" );
$caption = $captions->item(0)->nodeValue;
$note = $record->getElementsByTagName( "notes" );
$notes = $note->item(0)->nodeValue;
$dates = $record->getElementsByTagName( "date" );
$date = $dates->item(0)->nodeValue;
echo "<input type='checkbox' name='EntriesToRemove[]' value='" . $catId . "'> $title, "$location"<br>'n";
}
echo "<br><input type='submit' value='Delete Entry' />'n</form>'n";
?>
</body>
</html>
删除操作.php
<!doctype html>
<html>
<head>
<meta charset="UTF-8">
<title>Untitled Document</title>
</head>
<body>
<?
$entries_to_remove = $_POST['EntriesToRemove'];
$doc = new DOMDocument();
$doc->load("catalogue.xml");
$catalogue = $doc->getElementsByTagName("catalogue");
foreach($catalogue as $record) {
if($record['catId'] == $_POST["EntriesToRemove"]) {
// unset($record);
$catalogue->removeChild($record);
}
}
$doc->save("catalogue.xml");
?>
</body>
</html>
错误在线：
if($record['catId'] == $_POST["EntriesToRemove"]) {
我敢肯定，我错过了一些简单的问题
任何建议将不胜感激
非常感谢
您已经将EntriesToRemove设置为HTML中的数组 - 因此您需要检查catId是否是该数组的元素而不是等于它（如您链接的答案中所建议的那样）。但是你也需要正确地从 DOMDocument 中获取 catId 值（它不是一个数组） - 你实际上可以使用你在 HTML 中使用的代码来做到这一点，如下所示：
foreach($catalogue as $record) {
// Get the CatIds from this record
$catIds = $record->getElementsByTagName( "catId" );
// get the first CatId (you might actually want to check this exists
// first if you can't be sure the XML contains that key)
$catId = $catIds->item(0)->nodeValue;
// Look to see if the given catId is in the $_POST array
if (in_array($catId, $_POST['EntriesToRemove'])) {
// Found it!
}
}
。应该做这个伎俩。
编辑 我们循环浏览<record>条目的方式也存在问题。而且，由于在执行 removeChild 时修改 DOMDocument 的方式，您无法在foreach循环中删除（请参阅此处的评论：DOMNode：：removeChild）。相反，您要做的是存储要删除的节点的副本，然后将其删除到循环之外。
所以，我们最终得到的是：
$catalogue = $doc->getElementsByTagName("catalogue");
$records= $doc->getElementsByTagName('record');
$nodeToRemove= null;
foreach($records as $record) {
// Get the CatIds from this record
$catIds = $record->getElementsByTagName( "catId" );
// get the first CatId (you might actually want to check this exists
// first if you can't be sure the XML contains that key)
$catId = $catIds->item(0)->nodeValue;
// Look to see if the given catId is in the $_POST array
if (in_array($catId, $_POST['EntriesToRemove'])) {
// Found it! Store it for removal
$nodeToRemove= $record;
}
}
if ($nodeToRemove!=null) {
$oldnode= $nodeToRemove->parentNode->removeChild($nodeToRemove);
}
$doc->save('catalogue.xml');