我有如下字符串，我必须拆分：
Other,CODSITE,Items::getCodCdeCli+Address::getNameAddress
Other,CODSITE,Items::getCodCdeCli
Items::getCode+Address::getName,CODSITE+Items::getSample,Items::getItemID
Other, CODSITE, CODSITE2
到：
array(
array(
0 => 'Other',
1 => 'CODSITE',
2 => array(
'Items' => 'getCodCdeCli',
'Address' => 'getNameAddress'
)
),
//...
)
每个逗号都涉及新信息，如果我们有一个"+"，我们需要附加两个数据。如果我们有"：："，我们需要获取第一部分作为结果信息的关键。
为了开始这个解决方案，我试图将其拆分为逗号：
$re = "/([^,]+)/";
$str = "Other,CODSITE,Items::getCodCdeCli+Address::getNameAddress";
preg_match_all($re, $str, $matches);
现在有了这个正则表达式，我有这个：
array (size=2)
0 =>
array (size=3)
0 => string 'Other' (length=5)
1 => string 'CODSITE' (length=7)
2 => string 'Items::getCodCdeCli+Address::getNameAddress' (length=43)
1 =>
array (size=3)
0 => string 'Other' (length=5)
1 => string 'CODSITE' (length=7)
2 => string 'Items::getCodCdeCli+Address::getNameAddress' (length=43)
这是错误的。我有两次相同的结果..第 2 行 => [...] 没有拆分（这在我的正则表达式中是正常的）
单次传递的一种方法是使用如下所示array_combine函数：
$str = 'Other,CODSITE,Items::getCodCdeCli+Address::getNameAddress';
if ( preg_match_all('~(?|[,+]([^,+]+)::([^,+]+)|([^,]+))~', $str, $m) )
print_r( array_combine ( $m[1], $m[2] ) );
输出：
Array
(
[Other] =>
[CODSITE] =>
[Items] => getCodCdeCli
[Address] => getNameAddress
)
它必须是正则表达式吗？可以通过几个explode和foreach循环来实现这一点：
$str = 'Other,CODSITE,Items::getCodCdeCli+Address::getNameAddress';
//new entry per comma (,)
$results = explode(',',$str);
//check each entry for array information
foreach($results as &$result) {
if(strpos($result,'+') !== FALSE) {
//explode array information
$bits1 = explode('+',$result);
$result = array();
foreach($bits1 as &$subresult) {
//format array information into key => value pairs
if(strpos($subresult,'::') !== FALSE) {
$bits = explode('::',$subresult);
$result[$bits[0]] = $bits[1];
}
}
}
}
var_dump($results);
/**
* array (size=3)
* 0 => string 'Other' (length=5)
* 1 => string 'CODSITE' (length=7)
* 2 => array (size=2)
* 'Items' => string 'getCodCdeCli' (length=12)
* 'Address' => string 'getNameAddress' (length=14)
*/
在帕纳比-金@Richard答案的帮助下。这是解决方案，实际上即使我确定我们可以将其用于相同的结果，也不需要正则表达式。
$lines = array(
0 => 'Other,CODSITE,Items::getCodCdeCli+Address::getNameAddress',
2 => 'Other,CODSITE,Items::getCodCdeCli',
3 => 'Items::getCode+Address::getName,CODSITE+Items::getSample,Items::getItemID',
4 => 'Other, CODSITE, CODSITE2',
);
foreach ($lines as $input) {
$informations = explode(',', $input);
$result = array();
foreach ($informations as $information) {
if(strpos($information, '+') !== FALSE) {
$classes = explode('+',$information);
$temp = array();
foreach($classes as $subresult) {
if(strpos($subresult,'::') !== FALSE) {
$classAndMethod = explode('::',$subresult);
$temp[$classAndMethod[0]] = $classAndMethod[1];
} else {
$temp[] = trim($subresult);
}
}
$result[] = $temp;
} elseif (strpos($information, '::') !== FALSE) {
$classAndMethod = explode('::',$information);
$result[][$classAndMethod[0]] = $classAndMethod[1];
} else {
$result[] = trim($information);
}
}
var_dump($result);
}
它有效！