SQL 组并按两列排序

可能的重复项：
SQL 按"分组依据"内的总计排序

更新：我已经找到了我的解决方案，我在这里发布了。感谢大家的帮助！

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我正在开发一个需要排行榜的Facebook应用程序。记录完成游戏所需的分数和时间，并首先按分数组织，然后在两个相同分数的情况下使用时间。如果用户玩了多次，则使用他们的最佳分数。

分数越低，游戏中的表现越好。

我的表结构是：

id
facebook_id - (Unique Identifier for the user)
name
email
score
time - (time to complete game in seconds)
timestamp - (unix timestamp of entry)
date - (readable format of timestamp)
ip

我认为可行的查询是：

SELECT *
FROM entries
ORDER BY score ASC, time ASC
GROUP BY facebook_id

我遇到的问题是在某些情况下，它会在数据库中拉入用户的第一个分数，而不是他们的最高分数。我认为这取决于 GROUP BY 语句。我本以为 ORDER BY 语句会解决这个问题，但显然不是。

例如：

----------------------------------------------------------------------------
|  ID  |       NAME       |  SCORE  |  TIME  |  TIMESTAMP  |  DATE  |  IP  |
----------------------------------------------------------------------------
|  1   |  Joe Bloggs      |  65     |   300  | 1234567890  |  XXX   |  XXX |
----------------------------------------------------------------------------
|  2   |  Jane Doe        |  72     |   280  | 1234567890  |  XXX   |  XXX |
----------------------------------------------------------------------------
|  3   |  Joe Bloggs      |  55     |   285  | 1234567890  |  XXX   |  XXX |
----------------------------------------------------------------------------
|  4   |  Jane Doe        |  78     |   320  | 1234567890  |  XXX   |  XXX |
----------------------------------------------------------------------------

当我使用上面的查询时，我得到以下结果：

 1. Joe Bloggs - 65 - 300 - (Joes First Entry, not his best entry) 
 2. Jane Doe - 72 - 280

我本来以为...

 1. Joe Bloggs - 55 - 285 - (Joe's best entry)
 2. Jane Doe - 72 - 280 

这就像 Group By 忽略了顺序 - 只是覆盖了值。

将 MIN（score） 与分组依据一起使用会选择最低分数，这是正确的 - 但是它合并了数据库中用户第一条记录的时间，因此经常返回错误。

那么，如何选择用户的最高分数以及相关的时间、名称等，并按分数和时间对结果进行排序？

提前感谢！

select e.facebookid, minscore, min(e.time) as mintime -- or do you want maxtime?
from entries e join
     (select e.facebookid, min(score) as minscore
      from entries e
      group by facebookid
     ) esum
     on e.facebookid = esum.facebookid and
        e.score = e.minscore
group by e.facebookid, minscore

SELECT entries.facebook_id, MIN(entries.score) AS score, MIN(entries.time) AS time
FROM entries
    INNER JOIN (
        SELECT facebook_id, MIN(score) AS score
        FROM entries
        GROUP BY facebook_id) highscores
    ON highscores.facebook_id = entries.facebook_id
    AND entries.score = highscores.score
GROUP BY entries.facebook_id
ORDER BY MIN(entries.score) ASC, MIN(entries.time) ASC

    SELECT
      facebook_id,
      name,
      email,
      min(score) as high_score
    FROM
      entries
    GROUP BY
      facebook_id,
      name,
      email
   ORDER BY
     min(score) ASC

SELECT f.facebook_id, f.name, f.score, f.time FROM
    (SELECT facebook_id, name, min(score)
    AS highscore FROM golf_entries
    WHERE time > 0
    GROUP BY facebook_id)
AS x
INNER JOIN golf_entries as f
ON f.facebook_id = x.facebook_id
AND f.score = x.highscore
ORDER BY score ASC, time ASC

SELECT facebook_id, MIN(score), time, name, ... 
FROM entries 
GROUP BY facebook_id, time, name, ...
ORDER BY score, time