PHP/MySQL - 组合选择查询 - PHP/MySQL - Combine select queries

我有 3 个 MySQL 查询，如下所示;

$q1 = "SELECT id,date,quantity1,quantity2,total FROM test WHERE type='pencil' AND MONTH(date)='$month' AND YEAR(date)='$year' ORDER BY id";
$r1 = mysql_query($q1);
$q2 = "SELECT SUM(total) AS stotal FROM test WHERE type='pencil' AND MONTH(date)='$month' AND YEAR(date)='$year' GROUP BY id ORDER BY id";
$r2 = mysql_query($q2);
$q2 = "SELECT AVG(ROUND(total)) AS atotal FROM test WHERE type='pencil' AND MONTH(date)='$month' AND YEAR(date)='$year' GROUP BY id ORDER BY id";
$r2 = mysql_query($q2);

如何组合这 3 个查询？所以我可以在一个 while 循环中使用它。我已经尝试了 while 循环中的 MULTIPLE 语句，如下所示;

$lastr = '';
while ((list($id, $date, $q1, $q2, $total) = mysql_fetch_row($r1)) && ($row =  mysql_fetch_array($r2)) && ($row =  mysql_fetch_array($r3)))  {
if ($lastr != $id ) {
    if ($lastr != '') {
        // output row
    echo "<tr><th>$lastr</th><th>$stotal</th><th>$atotal</th><td>";
        echo join('</td><td>', $rowdata) . "</td></tr>'n";
    }
    $rowdata = $empty;
    $lastr = $id;
}
$rowdata[$rdate]  = $q1 .= '</td><td>' . $q2 .= '</td><td>' . $total;
}

当我只使用第一个查询时，所有内容都打印在我的表上，但是当我添加 2 个额外的"and"语句时，输出受到限制。顺便说一句，我试图生成一个动态列和行，仅当我在 while 循环中使用第一个查询时才有效。谢谢

非常感谢：Raheel Shan。

我的问题的答案是：

SELECT
  t.id,
  t.date,
  t.quantity1,
  t.quantity2,
  t.total,
  lt.stotal,
  lt.atotal
FROM test as t
  left join (select
           id,
           SUM(total)   AS stotal,
           AVG(ROUND(total)) AS atotal
         from test
         WHERE type = 'pencil'
         AND MONTH(date) = '$month'
         AND YEAR(date) = '$year'
         GROUP BY id) as lt
    on lt.id = t.id
WHERE type = 'pencil'
    AND MONTH(date) = '$month'
    AND YEAR(date) = '$year'
ORDER BY id

您可以使用此单个 derieved 查询

SELECT
  t.id,
  t.date,
  t.quantity1,
  t.quantity2,
  t.total,
  lt.stotal,
  lt.atotal
FROM test as t
  left join (select
           id,
           SUM(total)   AS stotal,
           AVG(ROUND(total)) AS atotal
         from test
         WHERE type = 'pencil'
         AND MONTH(date) = '$month'
         AND YEAR(date) = '$year'
         GROUP BY id) as lt
    on lt.id = t.id
WHERE type = 'pencil'
    AND MONTH(date) = '$month'
    AND YEAR(date) = '$year'
ORDER BY id

或者这更简单

SELECT
  t.id,
  t.date,
  t.quantity1,
  t.quantity2,
  t.total,
  SUM(lt.stotal) AS stotal,
  AVG(ROUND(lt.atotal)) AS atotal
FROM test as t
  left join test as lt
    on lt.id = t.id
WHERE type = 'pencil'
    AND MONTH(date) = '$month'
    AND YEAR(date) = '$year'
ORDER BY id

你可以这样组合......

SELECT id,date,quantity1,quantity2,total,(SELECT SUM(total)  FROM test WHERE type='pencil' AND MONTH(date)='$month' AND YEAR(date)='$year' GROUP BY id ORDER BY id) as sum_total,(SELECT AVG(ROUND(total))  FROM test WHERE type='pencil' AND MONTH(date)='$month' AND YEAR(date)='$year' GROUP BY id ORDER BY id") as avg_total FROM test WHERE type='pencil' AND MONTH(date)='$month' AND YEAR(date)='$year' ORDER BY id";

您可以像这样将查询添加在一起

$q1 = "SELECT id,date,quantity1,quantity2,total,AVG(ROUND(total)) AS stotal, AVG(ROUND(total)) AS atotal FROM test WHERE type='pencil' AND MONTH(date)='$month' AND YEAR(date)='$year' GROUP BY  id,date,quantity1,quantity2,total,stotal,atotal ORDER BY id";
$r1 = mysql_query($q1);

您需要 group by

子句的原因是，在 group by 语句之外不能有非加重选择，因为选择中存在加重函数。

希望这有帮助。

$q1 = "SELECT id,date,quantity1,quantity2,total,SUM(total) AS stotal,AVG(ROUND(total)) AS atotal FROM test WHERE type='pencil' AND MONTH(date)='$month' AND YEAR(date)='$year' ORDER BY id";
$r1 = mysql_query($q1);