zend在joinleft中选择查询 - zend select query inside joinleft

zend select query inside joinleft

本文关键字：选择查询 joinleft zend | 更新日期: 2023-09-27

如何在Zend模型的JOIN LEFT中编写SELECT查询？例如，如何将以下mysql查询转换为zend模型查询

    LEFT JOIN 
    (SELECT count(*) as game_count,topic_id,time as g_time from games_list WHERE type < 3 GROUP BY topic_id) t3
    ON chapter_list.id=t3.topic_id

我想添加具有以下zend查询的转换后的查询，并且我需要来自具有以下结果的上述查询的game_count。

    $query = $this->select()
    ->setIntegrityCheck(false)
    ->from(array('a' => 'chapter_list'), array('subtopic_id as topic','id as topic_id','grade','chapter_no as chapter','if(file_status=1,1,0) as ppt)','CONCAT("http://mysite.com?t=",subtopic_id) as link'))
    ->joinLeft(array('b' => 'subject_list'), 'a.subject = b.subject_id', array());
    return $this->fetchAll($query)->toArray();

最后我得到了它，

     $subquery1= $this->select()
    ->setIntegrityCheck(false)
    ->from('games_list', array('count(*) as game_count','topic_id','time as g_time'))
    ->where('type<?', 3)
    ->group('topic_id');
     //main query
     $query = $this->select()
    ->setIntegrityCheck(false)
    ->from(array('a' => 'chapter_list'), array('subtopic_id as topic','id as topic_id','grade','chapter_no as chapter','if(file_status=1,1,0) as ppt)','CONCAT("http://eskool.com/learn?t=",subtopic_id) as link'))
    ->joinLeft(array('b' => 'subject_list'), 'a.subject = b.subject_id', array())
    ->joinLeft(array('c' => $subquery1), 'a.id = c.topic_id', array('IFNULL(game_count,0)','g_time'))
    return $this->fetchAll($query)->toArray();