使用AJAX发送隐藏的ID输入字段


Send a hidden ID input field with AJAX

使用这个AJAX脚本,我正在尝试发送contentText和contentID的内容。

只发送contentTEXT是可行的,但我也想发送ID,这样我就可以对原始帖子发表评论。

但它不起作用!

myData在半工作时是这样的:

> var myData = '?content_txt='+$("#contentText").val(),
> '&content_id='+$("#contentId").val(); //build a post data structure

但我希望它是这样的,我认为

<script type="text/javascript"> $(document).ready(function() {
    //##### send add record Ajax request to response.php #########  $("#FormSubmit").click(function (e) {           e.preventDefault();             if($("#contentText").val()==='')            {
                alert("Please enter some text!");
                return false;           }
                        $("#FormSubmit").hide(); //hide submit button           $("#LoadingImage").show(); //show loading image
            var myData = '?content_txt='+$("#contentText").val(), '&content_id='+$("#contentId").val(); //build a post data structure
            jQuery.ajax({           type: "POST", // HTTP method POST or GET            url: "response.php", //Where to make Ajax calls             contentType: "application/x-www-form-urlencoded;charset=UTF-8",             dataType:"text", // Data type, HTML, json etc.          data:myData, //Form variables           success:function(response){
                $("#responds").append(response);
                $("#contentText").val(''); //empty text field on successful
                $("#FormSubmit").show(); //show submit button
                $("#LoadingImage").hide(); //hide loading image
            },          error:function (xhr, ajaxOptions, thrownError){
                $("#FormSubmit").show(); //show submit button
                $("#LoadingImage").hide(); //hide loading image
                alert(thrownError);             }           });     });
    //##### Send delete Ajax request to response.php #########  $("body").on("click", "#responds .del_button", function(e) {         e.preventDefault();         var clickedID = this.id.split('-'); //Split ID string (Split works as PHP explode)          var DbNumberID = clickedID[1]; //and get number from array          var myData = 'recordToDelete='+ DbNumberID; //build a post data structure
                $('#item_'+DbNumberID).addClass( "sel" ); //change background of this element by adding class       $(this).hide(); //hide currently clicked delete button
                    jQuery.ajax({           type: "POST", // HTTP method POST or GET            url: "response.php", //Where to make Ajax calls             dataType:"text", // Data type, HTML, json etc.          data:myData, //Form variables           success:function(response){
                //on success, hide  element user wants to delete.
                $('#item_'+DbNumberID).fadeOut();           },          error:function (xhr, ajaxOptions, thrownError){
                //On error, we alert user
                alert(thrownError);             }           });     });
}); </script>

我的表格我正在尝试使用

<form class="form-horizontal" accept-charset="utf-8">
<fieldset>
<legend><?php echo WORDING_ADD_A_COMMENT; ?></legend>
<!-- Textarea -->
<div class="control-group">
  <div class="controls">                     
    <textarea name="content_txt" id="contentText" cols="45" rows="5" placeholder="<?php echo WORDING_COMMENT_PLACEHOLDER; ?>"></textarea>
    <input type="hidden" name="content_id" id="contentId" value="<?php echo $_GET['topic_id']; ?>"/>
  </div>
</div>
<!-- Button -->
<div class="control-group">
  <label class="control-label" for="singlebutton"></label>
  <div class="controls">
    <button id="FormSubmit" class="btn btn-primary"><?php echo WORDING_BUTTON_COMMENT_BOX; ?></button>
    <img src="images/loading.gif" id="LoadingImage" style="display:none" />
  </div>
</div>
</fieldset>
</form>
var variable = {
 'content_txt': $("#contentText").val(),
 'content_id': $("#contentId").val() 
}; 

尝试使用

       var myData = '?content_txt='+$("#contentText").val()+'&content_id='+$("#contentId").val();

手动构建查询字符串时,仅使用?&,在这种情况下,还需要对值进行编码。

将数据作为参数发送时,最简单的解决方案是生成对象。这将由jQuery:自动编码

//build a post data structure
var myData = { 'content_txt': $("#contentText").val(),
               'content_id': $("#contentId").val() }; 

在使用表单时,您还可以序列化表单:

var myData = $('.form-horizontal').serialize();

data:'content_id='+$("#contentId").val()+'&content_txt='+$("#contentText").val(),