我很难找到一种方法来显示在我的分页页面上找到的结果，例如，如果搜索只有9个结果，我会得到"显示9个结果中的10个"，并且我希望它显示为"1-10个，11-20个，或1-9个，等等"。
这是代码。
<?php
$con = mysqli_connect("localhost", "root", "root", "courses");
// $total = mysqli_query($con, "SELECT count(title) as total")->fetch()['total']);
if(isset($_GET['searchword'])){
$searchword = $_GET['searchword'];
}
else {
$searchword = "";
}
$result = mysqli_query($con, "SELECT count(title) FROM course WHERE concat(award,' ',title) LIKE '%$searchword%'");
$row = mysqli_fetch_row($result);
// Total rows.
$rowstotal = $row[0];
//pages
$page = isset($_GET['page']) ? (int)$_GET['page'] : 1;
$perPage = isset($_GET['per-page']) && $_GET['per-page'] <= 100 ? (int)$_GET['per-page'] : 10;
$start = ($page > 1) ? ($page * $perPage) - $perPage : 0;
$pages = ceil($rowstotal / $perPage);
$sql = "SELECT * FROM course WHERE concat(award,' ',title) LIKE '%$searchword%' ORDER BY title ASC LIMIT {$start},{$perPage}";
$query = mysqli_query($con, $sql);
$resultsText = "$rowstotal results";
$resultsList = '';
while($row = mysqli_fetch_array($query, MYSQLI_ASSOC)){
$courseId = $row["id"];
$courseAward = $row["award"];
$courseName = $row["title"];
$courseDetails = $row["summary"];
$resultsList .= '<a href="course-page.php?id='.$courseId.'">'.$courseAward.' '.$courseName.'</a> <br>'.$courseDetails.'<br/>';
}
mysqli_close($con);
?>
<!DOCTYPE html>
<html lang="en">
<head>
<title>Courses</title>
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" rel="stylesheet">
<link rel="stylesheet" type="text/css" href="http://code.jquery.com/ui/1.11.4/themes/smoothness/jquery-ui.css">
<link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
<nav class="navbar navbar-default navbar-static-top navbar-inverse">
<div class="container">
<div class="navbar-header">
<a class="navbar-brand" href="#">
<img alt="Napier" src="">
</a>
</div>
</div>
</nav>
<div class="container">
<!-- Search -->
<form method="GET">
<input type="text" class="form-control" id="searchword" name="searchword" placeholder="Search" value="<?php echo $searchword ?>" style="width:30%;"><br>
</form>
<!-- Results -->
<div class="results">
<p></p>
<p>Showing <?php echo $perPage; ?> of <?php echo $resultsText; ?></p>
<p id="content"><?php echo $resultsList; ?></p>
</div>
<div class="pagination">
<?php for($x = 1; $x <= $pages; $x++): ?>
<a href="?page=<?php echo $x; ?>&per-page=<?php echo $perPage; ?>&searchword=<?php echo $searchword; ?>"<?php if($page === $x) { echo ' class="selected"'; } ?>><?php echo $x; ?></a>
<?php endfor; ?>
</div>
</div>
<script type="text/javascript" src="https://code.jquery.com/jquery-1.12.3.min.js"></script>
<script src="https://code.jquery.com/ui/1.11.4/jquery-ui.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('#searchword').autocomplete({
source: function(request, response){
$.ajax({
url:"auto.php",
dataType:"json",
data:{term:request.term},
success: function(data){
response(data.slice(0,10));
}
});
},
minLength: 1,
select: function(event,ui){
}
});
});
</script>
</body>
</html>
更新您的查询：
$sql = "SELECT SQL_CALC_FOUND_ROWS * FROM course WHERE concat(award,' ',title) LIKE '%$searchword%' ORDER BY title ASC LIMIT {$start},{$perPage}";
这个查询就在上面的查询下面。Select found_rows() as tot此tot将返回总行数（不考虑限制子句）