无法使用PHP数组格式化JSON响应


Unable to format JSON response with PHP Arrays

我想要以下JSON:

{"success": false,"errors": {"err1": "some error","err2": "another error"}}

我使用的代码:

$rs = array("success"=>true);
$rs['errors'][] = array("err1"=>"some error");
$rs['errors'][] = array("err2"=>"another error");
json_encode($rs);

生成以下内容:

{"success":false,"errors":[{"err1":"some error"},{"err2":"another error"}]}

errors应该是一个关联数组。

$rs = array('success' => false, 'errors' => array());
$rs['errors']['err1'] = 'some error';
$rs['errors']['err2'] = 'another error';
echo json_encode($rs);

errors在一个数字数组中包含一个对象,而不是多个对象。这应该有效:

$a = array(
  "success" => false,
  "errors" => array(
    "err1" => "some error",
    "err2" => "another error"
  )
);
json_encode($a);

您试图创建的JSON字符串中没有任何数组。它有嵌套的对象。您需要创建一个对象来复制JSON字符串,如下所示:

$root_obj = new StdClass();
$root_obj->success = false;
$root_obj->errors = new StdClass();
$root_obj->errors->err1 = 'some error';
$root_obj->errors->err2 = 'another error';