im将表单连接到数据库，但PHP正在为问题提供任何建议来帮助我的脚本
<?php
$connection = mysql_connect("localhost", "root", "");
$db = mysql_select_db("hot_data", $connection);
if(isset($_POST['submit']))
{
$userid=_$POST['userid'];
$first_name=$_POST['fname'];
$last_name=$_POST['lname'];
$livingadress=$_POST['ldress'];
$telephone=$_POST['phone'];
if($userid !=''||$telephone !=''){
//Insert Query of SQL
$query = mysql_query("INSERT INTO personal_data(userid,first_name,last_name,living_address,telephone)
VALUES('$userid','$first_name','$last_name','$livingaddress','$telephone')");
echo "<br/><br/><span>Data Inserted successfully...!!</span>";
}
else{
echo "<p>Insertion Failed <br/> Some Fields are Blank....!! </p>";
}
}
mysql_close($connection);
?>
<?php
try{
$servername = "localhost";
$username = "username";
$password = "password";
// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
throw new Exception("Connection failed: " . $conn->connect_error);
}
if (mysql_select_db("hot_data")){
if(isset($_POST['submit']))
{
$userid=$_POST['userid'];
$first_name=$_POST['fname'];
$last_name=$_POST['lname'];
$livingadress=$_POST['ldress'];
$telephone=$_POST['phone'];
if($userid !=''||$telephone !=''){
//Insert Query of SQL
$query = mysql_query("INSERT INTO personal_data(userid,first_name,last_name,living_address,telephone)
VALUES('{$userid}','{$first_name}','{$last_name}','{$livingaddress}','{$telephone}')");
throw new Exception("Data Inserted successfully...!!");
}
else{
throw new Exception("Insertion Failed...!!Some Fields are Blank....!!");
}
}
}else {throw new Exception("Could not find database....!! ");}
}catch(exception $ex)
{ echo $ex;
}
?>
你在这一行有一个错误 -
$userid=_$POST['userid'];
应该是这个——
$userid=$_POST['userid']; // $_POST variable was improperly written