我想知道是什么原因导致我的搜索结果在用户刷新页面后仍然显示,以及我如何修复它。PHP代码:
$con = mysql_connect($db_hostname,$db_username,$db_password);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db($db_database, $con);
if (!empty($_REQUEST['term'])) {
$term = mysql_real_escape_string($_REQUEST['term']);
$sql = "SELECT * FROM FUMUKU WHERE TimeD LIKE '%".$term."%'";
$r_query = mysql_query($sql);
while ($row = mysql_fetch_array($r_query)){
echo '<br /> Stock: ' .$row['Stock'];
echo '<br /> Price: ' .$row['Price'];
echo '<br /> Time: '.$row['TimeD'];
}
HTML代码:
<form action="" method="post">
Search: <input type="text" name="term" /><br />
<input type="submit" value="Submit" />
</form>
您的PHP脚本在页面加载时执行。为了防止这种情况,您需要在PHP代码的顶部添加if(isset($_POST['submit'])) {
,并将name="submit
添加到提交按钮中。
<?php
$con = mysql_connect($db_hostname,$db_username,$db_password);
if (!$con) {
die('Could not connect: ' . mysql_error());
}
if(isset($_POST['submit'])) {
if (!empty($_REQUEST['term'])) {
$term = mysql_real_escape_string($_REQUEST['term']);
$sql = "SELECT * FROM FUMUKU WHERE TimeD LIKE '%".$term."%'";
$r_query = mysql_query($sql);
while ($row = mysql_fetch_array($r_query)){
echo '<br /> Stock: ' .$row['Stock'];
echo '<br /> Price: ' .$row['Price'];
echo '<br /> Time: '.$row['TimeD'];
}
}
}
?>
<form method="post">
Search: <input type="text" name="term" /><br />
<input type="submit" name="submit" value="Submit" />
</form>