php-preg-match只获取最后匹配的字符串 - php preg match get only last matched string

php preg match get only last matched string

我需要获取最后一个HTTP头。我的字符串是：

HTTP/1.1 302 Moved Temporarily
Date: Sat, 30 Apr 2016 09:48:56 GMT
Server: Apache
X-Powered-By: PHP/5.5.34
Location: 2.php
Content-Length: 0
Content-Type: text/html
HTTP/1.1 302 Moved Temporarily
Date: Sat, 30 Apr 2016 09:48:57 GMT
Server: Apache
X-Powered-By: PHP/5.5.34
Location: 3.php
Content-Length: 0
Content-Type: text/html
HTTP/1.1 200 OK
Date: Sat, 30 Apr 2016 09:48:57 GMT
Server: Apache
X-Powered-By: PHP/5.5.34
Transfer-Encoding: chunked
Content-Type: text/html

但我需要最后一个头球。我试图用''n''n分解此字符串，但无法得到结果。是否可以使用preg_match进行此操作？

明白了！我需要用这个代码来破解它：

explode("'r'n'r'n", $header);

使用preg_split和array_pop函数的解决方案：

// $headers is your initial string
$headers_splitted = preg_split("/'R{2}/", $headers);
print_r(array_pop($headers_splitted));

输出：

HTTP/1.1 200 OK
Date: Sat, 30 Apr 2016 09:48:57 GMT
Server: Apache
X-Powered-By: PHP/5.5.34
Transfer-Encoding: chunked
Content-Type: text/html