PHP替换从当前位置到字符串末尾的最后一个字符 - PHP Replace last occurence of character from current position until the end of the string

PHP Replace last occurence of character from current position until the end of the string

我有这个字符串：

$string = '{"status":"2","vote":"1"},{"status":"1","vote":"0"}, "blabla"';

我想得到最后一个出现的"｝"的位置，并删除它后面的其余字符，然后追加"]"。请帮忙。谢谢

怎么样

$newString = substr($string,0,(strrpos($string,"}")+1))."]";

strrpos获取字符串最后一次出现的位置

http://php.net/manual/en/function.strrpos.php

$string = '{"status":"2","vote":"1"},{"status":"1","vote":"0"}, "blabla"';
$newString = (substr($string, 0, strrpos($string, "}") + 1))."]";
echo $newString; //results: {"status":"2","vote":"1"},{"status":"1","vote":"0"}]

使用本地json函数

$j=json_decode("[$string]");
array_pop($j);
echo json_encode($j);

否则你会遇到很多问题，比如在这种情况下：

 $string = '{"status":"2","vote":"1"},{"status":"1","vote":"0"}, "bla}bla"';

您必须使用PHP函数strrpos()，它将从右侧首次出现字符串。

echo $newString = substr($string,0,strrpos($string,"}")+1)."]";

输出

{"status":"2","vote":"1"},{"status":"1","vote":"0"}]

检查手动strrpos（）