在php中执行我自己的groovy脚本

嗨，我有这个groovy脚本（在$FRAPID_HOME/bin中），我想在Drupal:中调用它

#!/usr/bin/env groovy 
def cli = new CliBuilder(usage: 'frapid-generate-keys projectPath')
def opt = cli.parse(args)
if ( opt.h || opt.arguments().isEmpty() ) {
   cli.usage()
   return
}
def path = "."
println("Generating keys...")
def frapid = new Frapid()
println '---->' + opt.arguments()[0]
println("Keys genarated")
~             

php代码是这样的：

function api_manager_generate_keys_form_submit( $form, &$form_state) {
   $output = shell_exec( 'frapid-generate-keys '. $form_state['values']['api_manager_project_root'] );
   drupal_set_message( $output );
}

我的.bashrc配置是这样的：

export FRAPID_HOME=/home/admin1/frapid
export JAVA_HOME=/usr/lib/jvm/java-7-openjdk-i386
export GROOVY_HOME=/home/admin1/groovy-2.0.1
export CLASSPATH=$FRAPID_HOME/classes:$CLASSPATH
export PATH=$JAVA_HOME/bin:$PATH
export PATH=$GROOVY_HOME/bin:$PATH

当我尝试在drupal中执行时，apache给了我一个错误：

sh: 1: frapi-generate-keys: not found

然后我试着给出一条绝对路径：

$output = shell_exec( '/home/admin1/frapid/bin/frapid-generate-keys '. $form_state['values']['api_manager_project_root'] );

但仍有错误：

/usr/bin/env: groovy: No such file or directory