从连接了2个特性的表中选择一个产品


Select a product from a table with 2 property joined

我有一个类似的mysql表

PRODUCT
-------
product_id: 1 | name: product .... product_id: 2 | name: product2 .. etc etc

然后我有另一张桌子

PROPERTY
---
id: 1 | name: red | product_id: 1 .... id: 2 | name: large | product_id: 1 ..... id: 3 | name : brown | product_id: 2 .... and so on ...

如何选择具有2个属性的产品?

例如,我想拿一个具有RED和LARGE属性的产品

我试过

SELECT * FROM product
JOIN property USING (product_id)
WHERE property.name = "red" AND property.name = "large" ....

但显然它不起作用:)

谢谢你的帮助,对不起我的英语!

您需要计算其记录的实例

SELECT  a.productname
FROM    product a
        INNER JOIN property b
            on a.product_ID = b.product_ID
WHERE b.name IN ('red', 'large')
GROUP BY a.productname
HAVING COUNT(a.productname) = 2

如果单击演示,您可以看到对结果进行分组和使用IN 进行常规归档之间的差异

SQLFiddle演示

您应该使用OR:

SELECT * FROM product
JOIN property USING (product_id)
WHERE property.name = "red" OR property.name = "large" ....

此外,您还可以使用IN:

SELECT * FROM product
JOIN property USING (product_id)
WHERE property.name IN ('red', 'large') ....

也许类似

SELECT p.* 
  FROM product p
 WHERE EXISTS( SELECT * 
                 FROM property a
                WHERE a.name = 'red' 
                  AND a.product_id = p.product_id)
   AND EXISTS( SELECT * 
                 FROM property a
                WHERE a.name ='large' 
                  AND a.product_id = p.product_id)

可以工作吗?