当url没有这个时,如何获取图片扩展名和名称.(PHP)


How to get Image extention and name when url doesnot have this . (PHP)

我有一个格式的URL

www.domain.com/image.php?id=123&idlocation=987&number=01

它有必须下载的图像我使用以下功能下载

$codigo =  file_get_contents($url);

那么现在我如何使用$codigo 获得图像文件的外部

提前感谢

$path_parts = pathinfo('/www/htdocs/inc/lib.inc.php');
echo $path_parts['dirname'], "'n";
echo $path_parts['basename'], "'n";
echo $path_parts['extension'], "'n";
echo $path_parts['filename'], "'n"; // since PHP 5.2.0

请参考此链接以获取文件信息

http://php.net/manual/en/function.pathinfo.php