我有一个格式的URL
www.domain.com/image.php?id=123&idlocation=987&number=01
它有必须下载的图像我使用以下功能下载
$codigo = file_get_contents($url);
那么现在我如何使用$codigo
获得图像文件的外部
提前感谢
$path_parts = pathinfo('/www/htdocs/inc/lib.inc.php');
echo $path_parts['dirname'], "'n";
echo $path_parts['basename'], "'n";
echo $path_parts['extension'], "'n";
echo $path_parts['filename'], "'n"; // since PHP 5.2.0
请参考此链接以获取文件信息
http://php.net/manual/en/function.pathinfo.php