这是我的场景，我正在用codeigniter创建一个表单，我了解如何用模型等填充字段。我已经有了表单的布局。它现在正从我的索引函数中运行。我想存储给该表单的所有数据，并在postdata数组中访问它们，每个索引都是值的名称。请帮忙。CodeIgniter，PHP
创建表单
echo form_open('mycontroller/mymethod');
// rest of form functions
or <form name="myform" method="post" action="<?php echo site_url('mycontroler/mymethod');?>" > // rest of html form
then, in Mycontroller:
function mymethod()
{
$postarray = $this->input->post();
// you can pass it to a model to do the elaboration , see below
$this->myloadedmodel->elaborate_form($postarray)
}
Model:
function elaborate_form($postarray)
{
foreach($postarray as $field)
{
'' do your stuff
}
}
如果您想要XSS过滤，您可以在$this->input->post()调用中传递TRUE作为第二个参数。查看输入库上的用户指南
参见代码点火器的输入类
如何形成代码的一个例子是：
public function add_something()
{
if (strtolower($_SERVER['REQUEST_METHOD']) == 'post') { // if the form was submitted
$form = $this->input->post();
// <input name="field1" value="value1 ... => $form['field1'] = 'value1'
// you should do some checks here on the fields to make sure they each fits what you were expecting (validation, filtering ...)
// deal with your $form array, for exemple insert the content in the database
if ($it_worked) {
// redirect to the next page, so that F5/reload won't cause a resubmit
header('Location: next.php');
exit; // make sure it stops here
}
// something went wrong, add whatever you need to your view so they can display the error status on the form
}
// display the form
}
通过这种方式，您的表格将被显示，如果提交，其内容将被处理，如果发生错误，您将能够保留提交的值，以便在表格中预先输入它们，显示错误消息等。。。如果它有效，用户会被重定向到，他可以安全地重新加载页面，而无需多次提交。