$array变量不是'；当定义为$GLOBALS['；players'；][$name]=array( - $array variable isn't equal to $GLOBALS['players'][$name] when defined as $GLOBALS['players'][$name] = array()

$array variable isn't equal to $GLOBALS['players'][$name] when defined as $GLOBALS['players'][$name] = array()

使用下面的代码不起作用，但当我使用时

<?php
    $GLOBALS['players'] = array();
    function add($name) {
        $array = $GLOBALS['players'][$name] = array();
        array_push($array, "b");
    }
    add("a");
    print_r($players);
?>

（输出：Array（[a]=>Array（））此处的代码

<?php
    $GLOBALS['players'] = array();
    function add($name) {
        $array = $GLOBALS['players'][$name] = array();
        array_push($GLOBALS['players'][$name], "b");
    }
    add("a");
    print_r($players);
?>

（输出：Array（[a]=>Array（[0]=>b））工作正常。为什么$array在引用同一个数组时不起作用。

很简单，当您将值传递给$array时，您将$GLOBAL数组传递给一个新变量，而不是引用变量$GLOBAL变量。

简而言之：$array和$GLOBAL是两个不同的变量。这样做就像做：

$a = 10;
$b = $a;
$b++;
print_r($a); // Will not print 11, but 10, because you edited the var $b, that is different from $a.

要解决这个小问题您必须通过如下引用将变量传递给$array：

function add($name) {
    $GLOBALS['players'][$name] = array();
    $array = &$GLOBALS['players'][$name];
    array_push($array, "b");
}