所以，我的代码昨天非常适合我的网站......直到我意识到没有人的(1(出现在文档中!!我已经搜索了整个代码，似乎没有任何问题！
我不知道这是PHP(5.3(中的错误，还是其他什么....它只需要得到修复！
回顾：所有(1(都将因未知原因被删除(
我的代码在这里：
echo "Please wait while we submit your recipe...";
//getting form data
$thedate = Date("d-m-Y_H:i:s");
$title = $_POST['Title'];
$description = $_POST['Descript'];
$ingredients = $_POST['Ingredients'];
$instructions =$_POST['Instructions'];
$notes = $_POST['Notes'];
$name = $_POST['Name'];
//replacement for extra characters
$title = str_replace("''" && "'"", "" , $title);
$description = str_replace("''" && "'"", "" , $description);
$ingredients = str_replace("''" && "'"", "" , $ingredients);
$instructions = str_replace("''" && "'"", "" , $instructions);
$notes = str_replace("''" && "'"", "" , $notes);
$name = str_replace("''" && "'"", "" , $name);
$title = str_replace("''", "" , $title);
$the_recipe_url="RecibaseWaitingList/".$thedate."--".$title.".txt";
$the_recipe_url = str_replace("'", "" , $the_recipe_url);
$the_recipe_url = str_replace("'"", "" , $the_recipe_url);
$the_recipe_url = str_replace("?", "" , $the_recipe_url);
$the_recipe_url = str_replace(chr(10), "_", $the_recipe_url);
//bugs show up before or after this
echo '...';
//Checking to see if all required fields are filled
if($title !== '')
{
if($ingredients !=='')
{
if($instructions !=='')
{
//writing to the file
$writetothefile = fopen($the_recipe_url, 'c');
fwrite($writetothefile, $name." submitted this recipe on ".$thedate." 'r'n 'r'n ");
fwrite($writetothefile, "Title: ".$title." 'r'n ");
fwrite($writetothefile, $description." 'r'n ");
fwrite($writetothefile, " 'r'n ");
fwrite($writetothefile, "Ingredents:'r'n".$ingredients." 'r'n");
fwrite($writetothefile, " 'r'n ");
fwrite($writetothefile, "Instructions: 'r'n ".$instructions." 'r'n ");
fwrite($writetothefile, "'r'n ");
fwrite($writetothefile, "Notes: 'r'n" . $notes . "'r'n 'r'n ");
fwrite($writetothefile, "Thank you ".$name." for submitting this recipe! 'r'n 'r'n When you're done with the recipe, just click the back button.");
fclose($writetothefile);
//echo's for the user to see
echo '<br />Your recibase recipe url is <a href="' . $the_recipe_url . '">' . $the_recipe_url . '</a>.';
echo "<br />";
echo "<br />";
echo "Thank you for being so generous with your time and entering your recipe. We hope you enjoy using the rest of the site!< br />";
echo "<br />";
echo '<a href="http://recibase.musicsuper.org/input.php">Click Here</a> to enter in another recipe.<br />';
echo "...and we're done!";
}else{echo "Go back, and enter the <b><i>Instructions</i></b> of your recipe please!".'<br><br><a href="javascript:history.go(-1);">'.'<--- Go Back</a>';}
}else{echo "Go back, and enter the <b><i>Ingredients</i></b> in your recipe please!".'<br><br><a href="javascript:history.go(-1);">'.'<--- Go Back</a>';}
}else{echo "Go back, and enter the <b><i>Title</i></b> of your recipe please!".'<br><br><a href="javascript:history.go(-1);">'.'<--- Go Back</a>';
是什么导致 1 消失？为什么会这样？
任何想法将不胜感激。
如果您想查看此代码的产品以及贯穿其中的示例配方，请转到此处：http://recibase.musicsuper.org/AllOfYourRecipes/RecibaseWaitingList/15-02-2013_13:38:17--Deer%20Liver%20Pate.txt
&&是一个逻辑运算符。
$title = str_replace("''" && "'"", "" , $title);
如果你&&两个计算结果为(布尔(true的字符串，结果将是true。转换回字符串将1.因此，实际上您正在删除所有1。
你的问题是str_replace，特别是"''" && "'""。此语句等效于 1 ，因此您的str_replace实际上是str_replace(1, "" , $title);的。
您需要改用数组，因此代码将是
str_replace(array("''", "'""), "" , $title);
这将按照您的预期将数组元素的所有出现替换为空字符串。
我可能发现了你的问题：
您不能像这样使用此函数：
str_replace("''" && "'"", "" , $ingredients);
("''" && "'"")计算结果为TRUE为布尔值，"1"为字符串。
将数组传递给函数：
str_replace(array("''", "'""), "" , $ingredients);