在php中查找一周中的哪一天已经结束或尚未到来 - find the day of the week is finished or yet to come in php

find the day of the week is finished or yet to come in php

本文关键字：结束一天查找 php 一周 | 更新日期: 2023-09-27

例如，今天是星期三，如果用户在星期一输入，我需要说星期一已经过去了2天，如果想在php中找到它，我尝试了这个

      $S="2014-04-30 10:30:00";
      $firstDayOfWeek = 1; 
      $dateTime = new DateTime($s); 
      $difference = ($firstDayOfWeek - $dateTime->format('N'));
      echo $difference;
      echo "<br>";
      if ($difference > 0) { $difference -= 7; }
      $dateTime->modify("$difference days");
      var_dump($dateTime->format('r'));

尝试

$S="2014-04-30 10:30:00";
echo   $day_of_week = date('N'); // 3  - which will return 1 for Sunday through to 7 for Saturday
echo $day_of_my = date('N', strtotime($S)); // 3
//or $day_of_week = date('N', strtotime('Monday'));
$diff_days = $day_of_week - $day_of_my;  // 0
echo  'you are left'.$diff_days.' days';  // output 0

<?php
  $days = array(
    'Monday',
    'Tuesday',
    'Wednesday',
    'Thursday',
    'Friday',
    'Saturday',
    'Sunday',
  );
  $today = new DateTime();
  //$today = new DateTime('Friday'); //can set specific day if needed
  print "Today is " . $today->format('l') . "'n";
  foreach($days as $day) {
    $diff = new DateTime($day);
    $diff = $diff->format('N') - $today->format('N');
    if($diff > 0) {
      print "$day is $diff days in the future'n";
    }
    elseif($diff < 0) {
      $diff = abs($diff);
      print "$day is $diff days in the past'n";
    }
    else {
      print "$day is today'n";
    }
  }