PHP json解码如何显示选择的项目 - php json decode how to show select items

php json decode how to show select items

我使用这个php代码json解码facebook页面的专辑xml文件和回声每个专辑id。xml中的每个专辑都有data->id数组。

有一个id为"10150243262627075"的专辑，我不想让它被响应，但我想不出一个方法来让它工作。

任何帮助都将非常感激:)谢谢!

$json = json_decode($this->curlGetFile($this->URL));
if($json -> error) die("THERE HAS BEEN AN ERROR");
foreach($json->data as $v)
{
echo "Album Id: ".$v->id;
}

你错过的是继续;:)

$json = json_decode($this->curlGetFile($this->URL));
if($json -> error) die("THERE HAS BEEN AN ERROR");
foreach($json->data as $v)
{
     if($v->id == "10150243262627075") continue;
     echo "Album Id: ".$v->id;
}

 $json = json_decode($this->curlGetFile($this->URL));
 if($json -> error) die("THERE HAS BEEN AN ERROR");
 foreach($json->data as $v) {
      if($v->id != "10150243262627075") echo "Album Id: ".$v->id;
 }