我有一个问题,我有这个数组:
Array
(
[0] => Array
(
[date] => 2015-07-07
[nb] => 12
)
[1] => Array
(
[date] => 2015-07-10
[nb] => 6
)
[2] => Array
(
[date] => 2015-07-07
[nb] => 8
)
[3] => Array
(
[date] => 2015-07-09
[nb] => 48
)
[4] => Array
(
[date] => 2015-07-09
[nb] => 42
)
}
但是我想得到这个:
Array
(
[0] => Array
(
[date] => 2015-07-07
[nb] => 20
)
[1] => Array
(
[date] => 2015-07-09
[nb] => 90
)
[2] => Array
(
[date] => 2015-07-10
[nb] => 6
)
}
这个想法是如果数组中存在多个日期[nb]必须加起来。
我试过了:
foreach($aTotalRows as $k=>$row){
if($row[$k]['date'] == $row[$k+1]['date']){
$row[$k]['nb'] = $row[$k]['nb'] + $row[$k+1]['nb']
}
}
但不工作这个解决方案,你能帮我吗?提前致谢
不行,只有先按日期排序....才能正常工作试着构建如下代码:
$aggregateArray = array();
foreach($aTotalRows as $row) {
if(!array_key_exists($row['date'], $aggregateArray) {
$aggregateArray[$row['date']] = 0;
}
$aggregateArray[$row['date']] += $row['nb']
}
,它会给你这样的东西:
Array(
['2015-07-07'] => 20
['2015-07-10'] => 90
['2015-07-11'] => 6
)
你可以在必要的时候重新构造它
如果您想处理未排序的数组,您必须更改代码,如
$input = array(
array('date' => '2015-07-07', 'nb' => 12),
array('date' => '2015-07-10', 'nb' => 6),
array('date' => '2015-07-07', 'nb' => 8),
array('date' => '2015-07-09', 'nb' => 48),
array('date' => '2015-07-09', 'nb' => 42)
);
$required = array();
array_walk($input, function($v) use(&$required){
if(!isset($required[$v['date']])){ $required[$v['date']] = 0; }
$required[$v['date']] += $v['nb'];
});
$final = array_map(function($v, $k){
return array('date'=>$k, 'nb'=>$v);
}, $required, array_keys($required));
dump $required
array (size=3)
'2015-07-07' => int 20
'2015-07-10' => int 6
'2015-07-09' => int 90
dump of $final
array (size=3)
0 =>
array (size=2)
'date' => string '2015-07-07' (length=10)
'nb' => int 20
1 =>
array (size=2)
'date' => string '2015-07-10' (length=10)
'nb' => int 6
2 =>
array (size=2)
'date' => string '2015-07-09' (length=10)
'nb' => int 90
你可以在一个路径
$keys = array(); // array date => index in result
$i = 0;
foreach($input as $item)
if (isset($keys[$item['date']])) // if exist
$result[$keys[$item['date']]]['nb'] += $item['nb']; // add value
else {
$keys[$item['date']] = $i; // create new items in arrays
$result[$i++] = $item;
}
print_r($result);