我试图从一个网站创建JSON feed，我想在另一个网站上解码。问题是似乎有很多数组[0]，所以很难遍历它并计算有多少对象。
我如何在不获得所有这些数组的情况下进行编码和解码，以使其更容易计数对象的数量并循环遍历它。
现在我是这样编码的:
$data = array();
foreach ($posts as $post) {
$r = str_replace("'n",'', shorten_txt($post->post_content, 500));
$n = str_replace("'r", '', $r);
$post_data = array(
'title' => get_the_title($post->ID),
'link' => get_permalink($post->ID),
'image' => catch_that_image(),
'content' => $n,
'time' => get_the_date( $d)." ". get_the_time( $d));
$data[] = (array('item' => $post_data));
}
echo json_encode($data);
输出如下:
[
{
item: {
title: "Hello world!",
link: "http://URL/wordpress/?p=1",
image: "http://URL/wordpress/wp-content/uploads/2014/04/Digital-Board-2.png",
content: "Welcome to WordPress. This is your first post. Edit or delete it, then start blogging!",
time: "April 17, 2014 5:32 pm"
}
}
]
当我解码这个我得到这个:
Array ( [0] => Array ( [item] => Array( [title] => Hello world! [link] => http://URL/wordpress/?p=1 [image] => http://URL/wordpress/wp-content/uploads/2014/04/Digital-Board-2.png [content] => Welcome to WordPress. This is your first post. Edit or delete it, then start blogging! Jeg elsker kage [time] => April 17, 2014 5:32 pm ) ) )
解码码:
$json_string = 'http://95.85.11.40/wordpress/?page_id=20';
$jsondata = file_get_contents($json_string);
$obj = json_decode($jsondata, true);
print_r($obj);
如果你不想要这些array[0]位，那么就不要创建2D数组:
$data[] = (array('item' => $post_data));
应该是:
$data[] = $post_data;
您当前的语句读取为_add到数组$data一个数组，具有1键:"item"，而我的版本只是说:添加到$data的$post_data 的值。
输出解码后的数据:
$data = json_decode(file_get_contents($jsonFile), true);
foreach ($data as $idx => $item)
{
echo 'This is item number ', $idx +1, PHP_EOL;
print_r($item);
}