如何获取数据价格与分组日期?
SELECT store.date, store.pic, owner.name,
SUM (CASE WHEN [>>GROUPED store.date<<] THEN store.price) AS total_price
FROM store
JOIN owner
ON store.pic = owner.name GROUP BY store.date
，我想这样显示:
+-------------+------+------------+
| date | name | price |
+-------------+------+------------+
| 2016-09-30 | John | 100000.00 |
| 2016-09-29 | Rey | 125000.00 |
+-------------+------+------------+
试试这个可能会对你有帮助，
SELECT store.date, store.pic, owner.name,SUM(store.price) AS total_price
FROM store
JOIN OWNER ON store.pic = owner.name
GROUP BY store.date
我不明白你为什么在你的查询中使用case语句