我正在Laravel 5上通过AJAX进行文件上传。除了一件事,我几乎什么都做
。当我尝试上传一个太大(大于upload_max_filesize
和post_max_size
的文件时,我得到一个令牌不匹配异常。
意料之中的,因为我知道如果超过这些限制,我的输入将为空。空输入意味着没有收到_token
,因此负责验证CSRF令牌的中间件大惊小怪。
然而,我的问题不是抛出这个异常,而是它的呈现方式。当Laravel捕获此异常时,它会吐出通用Whoops页面的HTML(由于我处于调试模式,因此具有堆栈跟踪负载)。
处理此异常的最佳方法是什么,以便通过 AJAX 返回 JSON(或者在请求 JSON 时),同时保持默认行为?
编辑:无论抛出的异常如何,这似乎都会发生。我刚刚尝试通过 AJAX(数据类型:JSON)向不存在的"页面"发出请求,试图获取 404 并发生同样的事情 - 返回 HTML,没有任何 JSON 友好。
考虑到@Wader给出的答案和@Tyler Crompton的评论,我将自己尝试一下:
应用/异常/处理程序.php
/**
* Render an exception into an HTTP response.
*
* @param 'Illuminate'Http'Request $request
* @param 'Exception $e
* @return 'Illuminate'Http'Response
*/
public function render($request, Exception $e)
{
// If the request wants JSON (AJAX doesn't always want JSON)
if ($request->wantsJson()) {
// Define the response
$response = [
'errors' => 'Sorry, something went wrong.'
];
// If the app is in debug mode
if (config('app.debug')) {
// Add the exception class name, message and stack trace to response
$response['exception'] = get_class($e); // Reflection might be better here
$response['message'] = $e->getMessage();
$response['trace'] = $e->getTrace();
}
// Default response of 400
$status = 400;
// If this exception is an instance of HttpException
if ($this->isHttpException($e)) {
// Grab the HTTP status code from the Exception
$status = $e->getStatusCode();
}
// Return a JSON response with the response array and status code
return response()->json($response, $status);
}
// Default to the parent class' implementation of handler
return parent::render($request, $e);
}
在您的应用程序中,您应该有 app/Http/Middleware/VerifyCsrfToken.php
.在该文件中,您可以处理中间件的运行方式。因此,您可以检查请求是否是 ajax 并按照您喜欢的方式处理它。
或者,可能更好的解决方案是编辑异常处理程序以返回 json。请参阅app/exceptions/Handler.php
,如下所示的内容将是一个起点
public function render($request, Exception $e)
{
if ($request->ajax() || $request->wantsJson())
{
$json = [
'success' => false,
'error' => [
'code' => $e->getCode(),
'message' => $e->getMessage(),
],
];
return response()->json($json, 400);
}
return parent::render($request, $e);
}
基于@Jonathon的处理程序渲染函数,我只会修改条件以排除 ValidationException 实例。
// If the request wants JSON + exception is not ValidationException
if ($request->wantsJson() && ( ! $exception instanceof ValidationException))
如果适用,Laravel 5 已经在 JSON 中返回验证错误。
应用/异常/处理程序.php中的完整方法:
/**
* Render an exception into an HTTP response.
*
* @param 'Illuminate'Http'Request $request
* @param 'Exception $exception
* @return 'Illuminate'Http'Response
*/
public function render($request, Exception $exception)
{
// If the request wants JSON + exception is not ValidationException
if ($request->wantsJson() && ( ! $exception instanceof ValidationException))
{
// Define the response
$response = [
'errors' => 'Sorry, something went wrong.'
];
// If the app is in debug mode
if (config('app.debug'))
{
// Add the exception class name, message and stack trace to response
$response['exception'] = get_class($exception); // Reflection might be better here
$response['message'] = $exception->getMessage();
$response['trace'] = $exception->getTrace();
}
// Default response of 400
$status = 400;
// If this exception is an instance of HttpException
if ($this->isHttpException($exception))
{
// Grab the HTTP status code from the Exception
$status = $exception->getCode();
}
// Return a JSON response with the response array and status code
return response()->json($response, $status);
}
return parent::render($request, $exception);
}
我已经修改了这里找到的几个实现,以在Laravel 5.3上工作。主要区别在于我的将返回正确的HTTP状态文本
在 app''Exceptions''Handler 的 render() 函数中.php将此代码片段添加到顶部:
if ($request->wantsJson()) {
return $this->renderExceptionAsJson($request, $exception);
}
渲染异常作为Json的内容:
/**
* Render an exception into a JSON response
*
* @param $request
* @param Exception $exception
* @return SymfonyResponse
*/
protected function renderExceptionAsJson($request, Exception $exception)
{
// Currently converts AuthorizationException to 403 HttpException
// and ModelNotFoundException to 404 NotFoundHttpException
$exception = $this->prepareException($exception);
// Default response
$response = [
'error' => 'Sorry, something went wrong.'
];
// Add debug info if app is in debug mode
if (config('app.debug')) {
// Add the exception class name, message and stack trace to response
$response['exception'] = get_class($exception); // Reflection might be better here
$response['message'] = $exception->getMessage();
$response['trace'] = $exception->getTrace();
}
$status = 400;
// Build correct status codes and status texts
switch ($exception) {
case $exception instanceof ValidationException:
return $this->convertValidationExceptionToResponse($exception, $request);
case $exception instanceof AuthenticationException:
$status = 401;
$response['error'] = Response::$statusTexts[$status];
break;
case $this->isHttpException($exception):
$status = $exception->getStatusCode();
$response['error'] = Response::$statusTexts[$status];
break;
default:
break;
}
return response()->json($response, $status);
}
在 Laravel 8.x 中,你可以做
app/Http/Exceptions/Handler.php
public function render($request, Throwable $exception)
{
if ($request->wantsJson()) {
return parent::prepareJsonResponse($request, $exception);
}
return parent::render($request, $exception);
}
如果您想始终为所有异常返回 JSON,只需始终调用 parent::prepareJsonResponse
并删除parent::render
即可。
当 JSON 使用 APP_DEBUG=true
呈现时,您将获得完整的错误报告和堆栈跟踪。APP_DEBUG=false
时,您将收到一条通用消息,以便您不会意外暴露应用程序详细信息。
使用@Jonathon的代码,这里是Laravel/Lumen 5.3:)的快速修复
/**
* Render an exception into an HTTP response.
*
* @param 'Illuminate'Http'Request $request
* @param 'Exception $e
* @return 'Illuminate'Http'Response
*/
public function render($request, Exception $e)
{
// If the request wants JSON (AJAX doesn't always want JSON)
if ($request->wantsJson())
{
// Define the response
$response = [
'errors' => 'Sorry, something went wrong.'
];
// If the app is in debug mode
if (config('app.debug'))
{
// Add the exception class name, message and stack trace to response
$response['exception'] = get_class($e); // Reflection might be better here
$response['message'] = $e->getMessage();
$response['trace'] = $e->getTrace();
}
// Default response of 400
$status = 400;
// If this exception is an instance of HttpException
if ($e instanceof HttpException)
{
// Grab the HTTP status code from the Exception
$status = $e->getStatusCode();
}
// Return a JSON response with the response array and status code
return response()->json($response, $status);
}
// Default to the parent class' implementation of handler
return parent::render($request, $e);
}
我的方式:
// App'Exceptions'Handler.php
public function render($request, Throwable $e) {
if($request->is('api/*')) {
// Setting Accept header to 'application/json', the parent::render
// automatically transform your request to json format.
$request->headers->set('Accept', 'application/json');
}
return parent::render($request, $e);
}
你可以很容易地像这样捕捉到err.response:
axios.post().then().catch(function(err){
console.log(err.response); //is what you want
};