如何让Zend_Db只从大型查询中选择一列


How can I get Zend_Db to select one column only from a large query?

我在SQL中有一个相当复杂的查询,它在两个表之间执行计数。查询应该如下所示:

SELECT 
((SELECT COUNT(DISTINCT(pages.id)) AS `count` 
    FROM `pages` 
    INNER JOIN `pageRegions` ON pageRegions.pageId = pages.id 
    WHERE (MATCH (pages.name, pageRegions.contents) AGAINST ('+keyword*' IN BOOLEAN MODE))) + 
(SELECT COUNT(documents.id) AS `count` 
    FROM `documents` 
    INNER JOIN `files` ON files.id = documents.file 
    WHERE (MATCH (documents.name, 
              files.name, 
              files.extracted_text) AGAINST ('+keyword*' IN BOOLEAN MODE)))) AS count

不幸的是,当我使用Zend_Db获得以下代码时,查询包含了大量额外的列,因此添加两个查询显然都失败了:

$total_count_select = $PagesTable->getAdapter()
    ->query('((' . $pages_total_count_select . ') + 
              (' . $legal_resources_total_count_select . ')
             ) AS count');

其中$pages_total_count_select$legal_resources_total_count_select都是Zend_Db_Select对象。

我尝试使用columns()方法在每个选择对象上指定我想要的列,如下所示:

$legal_resources_total_count_select->columns('COUNT(documents.id) AS count');

但这似乎只是附加到选择查询上,而不是只返回指定的列。

所以Zend生成的查询最终看起来是这样的:

SELECT ((SELECT `pages`.*, 
                 ((1.3 * (MATCH(pages.name) AGAINST ('+keyword*' IN BOOLEAN MODE))) + 
                       (0.8 * (MATCH(pageRegions.contents) AGAINST ('+keyword*' IN BOOLEAN MODE)))) AS `score`, 
                     `pages`.`name` AS `page_name`, 
                     `pages`.`id` AS `page_id`, 
                     `pageRegions`.*, 
                     COUNT(DISTINCT(pages.id)) AS `count`
         FROM `pages`
         INNER JOIN `pageRegions` ON pageRegions.pageId = pages.id
         WHERE (MATCH (pages.name, pageRegions.contents) AGAINST ('+keyword*' IN BOOLEAN MODE))
         ORDER BY `score` DESC)
            + 
          (SELECT `documents`.*,
                   ((1.3 * (MATCH(documents.title) AGAINST ('+keyword*' IN BOOLEAN MODE))) + 
                       (0.8 * (MATCH(documents.short_description, files.NAME, files.extracted_text) AGAINST ('+keyword*' IN BOOLEAN MODE)))) AS `score`,
                     `files`.*, 
                    COUNT(documents.id) AS `count`
         FROM `documents`
         INNER JOIN `files` ON files.id = documents.file
         WHERE (MATCH (documents.title, documents.short_description, files.name, files.extracted_text) AGAINST ('+keyword*' IN BOOLEAN MODE))
         ORDER BY `score` DESC)
        ) AS COUNT

如何删除它选择的所有额外列?

您忘记了代码的一部分,即构造$pages_total_count_select$legal_resources_total_count_select的部分。

在构建这些列的过程中,您错过了一个参数,那就是您想要的列数组,如果您不给它它,它就会占用表。*.

因此,只需检查创建select的方式,然后添加一个带有空数组的参数。

更新:所以你做了:

$select = $this->select(Zend_Db_Table::SELECT_WITH_FROM_PART);

在那之后,用Zend_Db_Table(此处为$this)重做->from()调用,您可以在此处指定列,因此可以指定一个空数组或唯一需要的数组:

$select = $this->select(Zend_Db_Table::SELECT_WITH_FROM_PART);
$select->from($this, array(new Zend_Db_Expr('COUNT(documents.id) AS count')));