两张日期邮票,呼应其间的每一天


Two date stamps, echo something for every day in between

好吧,假设我在数据库中保存了两个时间戳,格式为yyyymmdd,一个开始日期和结束日期。

假设这些是我的开始和结束日期:20110618-20110630

我怎么能让它一直呼应20110618、20110619、20110620等直到20110630?

// Will return the number of days between the two dates passed in
function count_days( $a, $b ) {
    // First we need to break these dates into their constituent parts:
    $gd_a = getdate( $a );
    $gd_b = getdate( $b );
    // Now recreate these timestamps, based upon noon on each day
    // The specific time doesn't matter but it must be the same each day
    $a_new = mktime( 12, 0, 0, $gd_a['mon'], $gd_a['mday'], $gd_a['year'] );
    $b_new = mktime( 12, 0, 0, $gd_b['mon'], $gd_b['mday'], $gd_b['year'] );
    // Subtract these two numbers and divide by the number of seconds in a
    //  day. Round the result since crossing over a daylight savings time
    //  barrier will cause this time to be off by an hour or two.
    return round( abs( $a_new - $b_new ) / 86400 );
}
// Prepare a few dates
$date1 = strtotime( '20110618' );
$date2 = strtotime( '20110630' );
// Calculate the differences, they should be 43 & 11353
echo "<p>There are ", count_days( $date1, $date2 ), " days.</p>'n";
$days = count_days($date1, $date2);
for ($i = 0; $i < $days; $i++) {
    echo date('Ymd', $date1+(86400*$i));
}

使用函数from:获取两个日期之间的天数。

这应该会在PHP 5.3 上为您打印所有日期

$start = '20110618';
$end = '20110630';
$date = new DateTime($start);
$end = new DateTime($end)->getTimestamp();
while ($date->getTimestamp() <= $end) {
    echo $date->format('Ymd');
    $date->add(new DateInterval('P1D'));
}

使用PHP日期时间对象,因此以下将是persudo代码

//Convert the 2 dates to a php datetime object
//Get the number of days differance inbetween
//For each day, 
      //create a new datetime object, N days after the youngest object
      //Echo the reasult out

你就不能做这样的事情吗(经过编辑以包含实际的php循环)

$date = new DateTime('20110618');
do {
    $d = $date->format('Ymd') . "'n";
    echo $d;
    $date->add(new DateInterval('P1D'));
} while ($d < 20110630);